最新のA00-282問題集で試験を準備する

SASInstitute A00-282 試験概要:

SASInstitute A00-282 試験シラバストピック:

SASInstitute Clinical Trials Programming Using SAS 9.4 認定 A00-282 試験問題：

1. This question will ask you to provide a line of missing code.

Which line of code would produce the blue notes in the log?

A) %if indm ne indisp %then %put 'MERGE ISSUE: ' subjid= indm= indisp=;
B) if indm ne indisp then output 'MERGE ISSUE: ' subjid indm indisp;
C) if indm ne indisp then put 'MERGE ISSUE: ' _all_;
D) if indm ne indisp then put 'MERGE ISSUE: ' subjid= indm= indisp=;

2. This question will ask you to provide a line of missing code.
Given the following demography (DM) data set sorted by site with character variables SUBJID, SITE, SEX, RACE and numeric variables ENROLLDAT and DOB:

The following SAS program is submitted:
%macro p_demog(bylist, varlist, statlist=);
proc sort data=derived.dm out=dm;
by &bylist;
proc means data=dm;
by &bylist;
var &varlist;
output out=stats &statlist;
run;
%mend p_demog;
Which call to the p_demog macro provides only the MEAN of AGE by SEX into the output dataset STATS?

A) %p_demog(sex age statlist=%str(mean=mymeanvar))
B) %p_demog(statlist=%str(mean=mymeanvar), sex, varlist=age)
C) %p_demog(sex, age, statlist=%str(mean=mymeanvar))
D) %p_demog(statlist=%str(mean=mymeanvar), sex, age)

3. Given the following complete dataset (WORK.TESTDM) with the variables USUBJID (character) and AGE (numeric):

The following code is executed:
proc sql;
select age into: age separated by ','
from testdm;
quit;
What is the value of the macro variable AGE?

A) Blank, the code will not execute
B) 17, 17, 4, 3, 6
C) 17.1 17.7 4.4 3.8 6.3
D) 17.1,17.7,4.4,3.8,6.3

4. The following SAS program is submitted:

What is the value of the second variable in the data set WORK.DIGESTL?

A) divertic
B) diverticulosis
C) No variables are created.
D) a missing value

5. Study day is defined as DCMDATE minus RFSTDTC +1

Which statement will compute the study day correctly without producing notes for missing values in the log?

A) STUDYDAY=input(DCMDATE,yymmdd8.)-input(RFSTDTC,date9.)+1;
B) If RFSTDTC^='' and length(DCMDATE)=8 then STUDYDAY=input(DCMDATE,date9.)- input(RFSTDTC,yymmdd8.)+1;
C) STUDYDAY=DCMDATE-RFSTDTC+1;
D) If RFSTDTC^='' and length(DCMDATE)=8 then STUDYDAY=input(DCMDATE,yymmdd8.)- input(RFSTDTC,date9.)+1;

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